NEB Class 11 • Physics • Geometrical Optics
Dispersion: NEB Class 11 Physics Guide
Explain why one white beam becomes a spread of wavelengths. Connect refractive index, prism deviation, colour order, rainbows and optical design without treating colour bands as separate substances.
- Wavelength-dependent refractive index
- Prism spectrum and angular dispersion
- Rainbows, aberration, experiments and applications
Curriculum boundary
What dispersion adds to prism refraction
The CDC secondary curriculum includes dispersion in geometrical optics; check the CDC Physics Grade 11 page for current Nepal resources. Review Refraction through Prisms before adding wavelength dependence.
The definitions and physical explanations here are cross-checked with OpenStax dispersion, rainbows and prisms and OpenStax University Physics dispersion.
Physical cause
Refractive index depends on wavelength
At a stationary boundary, frequency remains fixed while speed and wavelength change in the medium. The material’s refractive index n(λ) is not exactly the same for every wavelength. Snell’s law n₁sin i=n₂sin r therefore gives slightly different refraction angles to different spectral components entering the same prism.
For many transparent materials in the visible range under normal dispersion, nviolet>nred. Violet slows more in the optical model and bends more toward the normal on entry, then more away from the normal on exit. The net prism deviation is therefore greater for violet than red. State “for ordinary visible-light glass” rather than treating this order as a universal law for every material and wavelength.
Prism geometry
From one deviation to a family of deviations
For a monochromatic ray through a prism, A=r₁+r₂ and δ=i+e−A. At minimum deviation, i=e and r₁=r₂=A/2, giving n=sin[(A+δm)/2]/sin(A/2) for a prism in air. White light needs one refractive index and one minimum deviation for each wavelength.
Two-colour comparison
For a 60° prism, suppose nred=1.510 and nviolet=1.530. Then δm,r=2sin⁻¹(1.510sin30°)−60°≈38.1°, while δm,v≈40.0°. The angular spread is about 1.9° for the supplied illustrative data.
For a thin prism and small angles in radians, δ≈(n−1)A. Angular dispersion between violet and red is Δδ≈(nv−nr)A. This is an approximation, so do not use it uncritically for a large-angle prism.
Continuous spectrum
Colour labels sample a wavelength continuum
Red, orange, yellow, green, blue and violet are useful names, sometimes with indigo added, but a prism produces a continuous distribution rather than six or seven physically separated packets. Perceived colour also depends on the spectrum reaching the eye and the visual response.
| Observation | Physics conclusion | Common error |
|---|---|---|
| White beam spreads | Direction depends on wavelength | Prism “creates” colours |
| Violet deviates more in ordinary glass | n is larger at shorter visible wavelength | Frequency changed at boundary |
| Second inverted prism can recombine | Components can overlap again | Colours were destroyed |
| Narrow slit gives cleaner bands | Source angular width limits resolution | Slit changes wavelength |
Atmospheric application
A rainbow uses refraction, reflection and geometry
Sunlight entering a water droplet is refracted and dispersed, internally reflected, then refracted again as it exits. Different wavelengths leave a droplet at different directions. An observer receives a given colour from droplets positioned at the appropriate angle, so the visible arc is an angular selection from many droplets—not a coloured physical band at one fixed distance.
A primary rainbow and a laboratory prism both separate wavelengths, but their paths differ. Do not reduce the rainbow to “total internal reflection only”; entry and exit refraction plus internal reflection are all essential in the basic geometric model.
Optical consequence
Chromatic aberration is unwanted dispersion
A simple lens can have different focal lengths for different wavelengths because n varies with λ. White-light images may show coloured fringes or wavelength-dependent focus. Combining lens elements made from different glasses can reduce chromatic aberration over selected wavelengths, but no introductory correction should be described as perfect for all colours and field positions.
Dispersion is also useful: prisms and diffraction-based instruments separate spectra for material identification, astronomy and wavelength measurement. In communication media, wavelength-dependent group delay can broaden pulses. Always specify whether dispersion is helping measurement or limiting image or signal quality.
Practical investigation
Observe a spectrum safely and measure carefully
- Use a teacher-approved white-light source and narrow slit; never look into a laser or intense beam.
- Align the slit, prism and screen at a common height.
- Rotate the prism to obtain a clear spectrum.
- Mark red and violet extremes on paper without placing eyes in the beam.
- Measure screen distance and colour separation to estimate angular spread for small angles.
- Repeat after realignment and report uncertainty from band width and position judgement.
A broader slit increases brightness but makes each wavelength’s image wider, reducing separation clarity. Ambient light lowers contrast. Prism material, apex angle, source spectrum, screen distance and alignment all affect the observation. Use PhET Bending Light to review wavelength-sensitive refraction after making a prediction.
Worked reasoning
Derive, calculate and interpret
Thin-prism angular dispersion
A=5°=0.0873 rad, nv=1.532 and nr=1.514. Δδ≈(0.018)(0.0873)=0.00157 rad≈0.090°. At a 2.0 m screen distance, small-angle separation y≈LΔδ≈3.1 mm.
Dispersive power model
A common school definition compares angular dispersion with mean deviation, for example ω=(nv−nr)/(nmean−1). Write exactly which reference index or colour is used. It is a property comparison within the chosen wavelengths, not a power in watts.
Common mistakes and repair
- Calling the spectrum seven discrete wavelengths: state that it is continuous.
- Saying frequency changes at entry: frequency is fixed by the source and boundary continuity.
- Using thin-prism equations without a small-angle statement.
- Confusing dispersion with scattering or diffraction: identify the wavelength-dependent mechanism.
- Describing a rainbow with refraction alone: include internal reflection and observer geometry.
- Using exact-looking glass indices without stating that material and wavelength determine them.
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Frequently asked questions
Questions students ask about dispersion
Does a prism create colours?
No. It separates wavelength components already present in the incident light because their refraction and deviation differ.
Why does violet usually deviate more than red?
For ordinary glass in the visible range, refractive index is generally larger at shorter wavelengths, so violet experiences greater net deviation.
Is a spectrum really seven colours?
It is continuous. Named colour bands are useful perceptual and educational labels within that continuum.
Is dispersion the same as diffraction?
No. Both can separate wavelengths, but prism dispersion uses wavelength-dependent refractive index, while diffraction uses interference from apertures or structures.
Why do lenses show coloured fringes?
Wavelength-dependent refractive index can give different focal lengths, producing chromatic aberration in a simple lens.
Where can I get help with dispersion?
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References and next steps
Sources and related study guides
- CDC Nepal: Physics Grade 11
- CDC Nepal: Secondary Curriculum
- OpenStax: Dispersion, Rainbow and Prisms
- OpenStax University Physics: Dispersion
- OpenStax: Refraction
- PhET: Bending Light
Continue with the Dispersion Study Guide and compare chromatic focus with the Lenses guide. Curriculum scope and sources were checked on 2 August 2026; follow current CDC, NEB and college instructions if requirements change.
Mechanism comparison
Separate dispersion, diffraction and scattering
| Phenomenon | Wavelength dependence | Typical clue |
|---|---|---|
| Prism dispersion | Refractive index n(λ) | Refraction through material with different deviations |
| Diffraction | Pattern scale depends on λ and aperture | Spreading and interference near slits or gratings |
| Rayleigh-type scattering | Shorter visible wavelengths scatter more strongly in a small-particle regime | Light redirected through a medium, not a prism spectrum |
All three can produce colour-dependent observations, but the causal model, geometry and equations differ. A diffraction grating can separate wavelengths without relying on refractive-index variation. Atmospheric colour cannot be explained by saying “air acts like a prism” in every situation.
Recombination test
Place a second identical prism with opposite orientation after the first spectrum and align it so wavelength-dependent deviations are reversed. The emerging components can overlap into a near-white beam. This demonstrates that the first prism separated existing components; it did not permanently change them into new substances.
Resolution versus dispersion
A larger angular spread can help separate nearby wavelengths, but a spectrometer’s ability to resolve them also depends on slit width, aberration, detector sampling, diffraction and signal quality. Do not equate “more colourful” with automatically more precise measurement.
In an exam comparison, state the controlling wavelength dependence first, draw the geometry second, then name the observation. This ordering prevents rainbow, prism, grating and blue-sky explanations from collapsing into one vague statement.
Final mechanism check: name the source spectrum, wavelength-dependent property, optical geometry and measured observation. State the wavelength range and any small-angle assumption before treating a colour trend as general.
Ask about online or physical tuition
For focused Class 11 and Class 12 subject tuition, lesson clarification, worked-example practice and exam preparation, call 9846662070. Class mode, timetable, teacher availability and fees should be confirmed directly before enrolment.
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