NEB Class 11 • Physics • Geometrical Optics

Lenses: NEB Class 11 Physics Guide

Connect refraction at two curved surfaces to principal rays, image formation and the thin-lens equation. Use one physical prediction to check every calculation.

  • Convex and concave lens models
  • Ray diagrams, formula, power and magnification
  • Worked examples, practical method and exam checks
Convex lens ray diagramTwo principal rays from an object pass through a convex lens and meet at a real inverted image.
A diagram should predict the sign and size of the image.

Learning boundary

What the NEB lens topic asks you to connect

The CDC secondary curriculum includes focal length of a convex lens and geometrical-optics relations. Check the CDC Physics Grade 11 page for current Nepal materials. This guide develops the same ideas with the institutional treatments in OpenStax image formation by lenses and OpenStax high-school lenses.

Prerequisites are refraction, a normal to a surface, refractive index, similar triangles and reciprocal algebra. Review Refraction at Plane Surfaces before deriving lens behaviour.

Optical language

Name each point before drawing rays

Optical centre O

Central reference point of the thin-lens model. A principal ray through O is treated as undeviated.

Principal axis

Straight reference line through the optical centre and centres of curvature.

Principal foci F

Points related to incident or emerging rays parallel to the principal axis.

Focal length f

Signed distance from O to a principal focus; optical power is its reciprocal in metres.

A lens thicker at the centre than the edge is usually converging in air; one thinner at the centre is usually diverging. The surrounding medium matters: convergence is not determined by shape alone in every possible medium.

Construction method

Use principal rays as evidence

  1. Draw the axis, lens line, O and equal focal marks on both sides.
  2. Place the object relative to F and 2F.
  3. From its tip draw a ray parallel to the axis. A converging lens sends it through the far focus; a diverging lens sends it as if from the near focus.
  4. Draw a ray through O with negligible deflection in the thin-lens model.
  5. Use a focus-to-parallel ray as a check.
  6. Mark the image where real rays meet or where dashed backward extensions appear to meet.

Do not bend the centre ray at O merely to make it intersect. Do not extend real rays backwards with solid lines. A partial aperture still admits rays from every object point, so it makes the full image dimmer rather than cutting away exactly half of it.

Image prediction

Map object region to image nature

Lens and objectImage positionNature
Convex beyond 2FF to 2FReal, inverted, diminished
Convex at 2FAt 2FReal, inverted, same size
Convex between F and 2FBeyond 2FReal, inverted, enlarged
Convex at FInfinity ideallyEmergent rays parallel
Convex inside FObject sideVirtual, upright, enlarged
Concave, any real objectObject side, O to FVirtual, upright, diminished

Reconstruct the table from ray rules rather than memorising six isolated lines. The screen test is decisive: real rays can form a sharp image on a screen; a virtual image cannot be caught directly without another optical element.

Quantitative model

Make the equation agree with the diagram

In the OpenStax real-is-positive convention, 1/f=1/do+1/di and m=hi/ho=−di/do. Real image distance is positive, virtual image distance negative, converging f positive and diverging f negative. Your school may use a Cartesian convention; state it and do not mix signs from different systems.

Convex real image

A convex lens has f=12 cm and a real object at do=36 cm. Then 1/di=1/12−1/36=1/18, so di=18 cm and m=−18/36=−0.50. The image is real, inverted and half-sized, matching an object beyond 2F.

Convex magnifier

For f=10 cm and do=7.5 cm, 1/di=0.10−0.1333=−0.0333 cm⁻¹, so di≈−30 cm and m=+4.0. The negative image distance and positive magnification describe an upright enlarged virtual image.

Concave lens

For f=−15 cm and do=30 cm, 1/di=−1/15−1/30=−1/10, so di=−10 cm and m=+1/3. This is upright, diminished and virtual.

Focal strength

Convert focal length to lens power

P=1/f when f is in metres, so power is measured in dioptres (D). A +2.5 D lens has f=+0.40 m. A −4.0 D lens has f=−0.25 m. Convert centimetres to metres before taking the reciprocal; a 20 cm converging lens is +5 D, not 0.05 D.

For thin lenses in contact in the paraxial approximation, powers add: Peq=P₁+P₂. A +5 D and −2 D pair gives +3 D, or f≈0.333 m. State that spacing, thickness and aberrations limit this simple model.

Laboratory evidence

Measure focal length safely and critically

Use an illuminated distant object—not the Sun—and form a sharp image on a screen with a convex lens. Measure from O to the screen for an approximate focal length. Repeat after refocusing and quote the spread. A finite object distance, lens thickness, parallax, screen judgement and imperfect alignment cause uncertainty.

For a u–v method, take several object distances greater than f, focus the screen, and record do and di. Calculate f for each trial or plot 1/di against 1/do. The equation predicts intercept 1/f and gradient −1 under the chosen axes. Use PhET Geometric Optics after predicting each movement.

Design reasoning

Choose a lens from the required image

A camera needs a real image on a sensor; a magnifier uses a convex lens with the object inside F; a diverging corrective lens can reduce effective convergence for myopia. A compound microscope and telescope use more than one lens, so analyse one image stage at a time. Do not recommend a spectacle power from a classroom calculation—eye care requires a qualified professional.

Common mistakes and repair

  • Angles or distances measured from a surface rather than O: redraw the axis and reference.
  • Using centimetres in P=1/f: convert to metres first.
  • Calling every convex-lens image real: check whether the object is outside F.
  • Giving only a number: interpret image side, orientation and size.
  • Mixing mirror and lens ray rules: label reflection or refraction at the device.
  • Using a formula without a sketch: make a region prediction before algebra.

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Frequently asked questions

Questions students ask about lenses

Why does a convex lens sometimes make a virtual image?

When a real object is inside its focal length, emerging rays diverge and their backward extensions meet on the object side, producing an upright enlarged virtual image.

Can a concave lens form a real image?

For a single concave lens with a real object, the image is virtual, upright and diminished. More complex systems or virtual objects require separate analysis.

Why must power use metres?

The dioptre is reciprocal metre, so focal length in centimetres must be divided by 100 before applying P=1/f.

How many rays should I draw?

Two accurate principal rays locate the image; a third ray is a valuable construction check.

What is the best numerical check?

Confirm that the calculated image region, orientation and size agree with a ray diagram and with limiting cases near F and far away.

Where can I get help with lenses?

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References and next steps

Sources and related study guides

Continue with the Lenses Study Guide and use the Physical Quantities guide for unit and uncertainty review. Curriculum scope and sources were checked on 2 August 2026; follow current CDC, NEB and college instructions if requirements change.

Integrated transfer

Trace an image through two lens stages

Compound optical instruments are best handled one stage at a time. Suppose a first convex lens forms a real inverted intermediate image. That image becomes the object for a second lens, and its object distance is determined by the separation between the second lens and the intermediate image—not automatically by the original object distance. Draw the intermediate image before writing the second equation.

Two converging lenses

Lens 1 has f₁=10 cm and receives a real object at 30 cm, so its image forms 15 cm to the right. Lens 2 is 25 cm to the right of lens 1, making the intermediate image a real object 10 cm to its left. If f₂=8 cm, then 1/d₂=1/8−1/10=1/40 and the final image forms 40 cm to the right of lens 2. Magnifications are m₁=−0.50 and m₂=−4, so total magnification m=m₁m₂=+2: final orientation is upright relative to the original object.

This stage method also reveals model limits. If the intermediate image would lie beyond the second lens, it may act as a virtual object and the chosen sign convention must handle that case explicitly. Lens separation means powers cannot simply be added as though the elements were in contact.

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