NEB Class 11 • Physics • Geometrical Optics
Refraction through Prisms: NEB Class 11 Physics Guide
Trace a ray across two non-parallel faces, build the deviation relation, use minimum-deviation symmetry and understand when the thin-prism approximation applies.
- Prism angle and two-surface geometry
- Deviation and minimum-deviation relation
- Thin prisms, dispersion, experiments and examples
Curriculum boundary
What prism refraction includes
The CDC secondary curriculum includes minimum deviation, refractive index and deviation by a small-angle prism. Check the CDC Physics Grade 11 page for current Nepal resources.
Review OpenStax Snell’s law before treating two faces. The OpenStax refraction and prism overview connects refractive index with prism bending and dispersion.
Two boundaries
Name every prism angle
The apex angle A is between the two refracting faces. At face 1, incident angle i and internal refraction r₁ are measured from its normal. At face 2, internal angle r₂ and emergence angle e are measured from the second normal. Geometry inside gives A=r₁+r₂.
Deviation δ is the angle between the original incident direction extended and the emergent ray. It is not the emergence angle. For a prism in the usual orientation the net ray deviates toward the base.
Build the relation
Why δ=i+e−A
Deviation at face 1 is i−r₁, and at face 2 it is e−r₂. Adding gives δ=i+e−(r₁+r₂). Since r₁+r₂=A, δ=i+e−A.
Direct geometry
A=60°, i=48° and e=42°. δ=48+42−60=30°. Also r₁+r₂ must total 60°.
Find emergence
A=50°, i=40° and δ=25°. e=δ+A−i=35°.
Each surface still obeys Snell’s law. Use nairsin i=nprismsin r₁ and nprismsin r₂=nairsin e.
Symmetric path
Minimum deviation and refractive index
As incidence changes, deviation falls to a minimum then rises. At the minimum for a reversible prism path, i=e and r₁=r₂=A/2. From δm=2i−A, i=(A+δm)/2.
Apply Snell’s law at the first face for a prism in air: n=sin i/sin r₁=sin[(A+δm)/2]/sin(A/2).
Find prism index
A=60° and δm=40°. n=sin50°/sin30°≈0.766/0.5≈1.53.
Find minimum deviation
n=1.50 and A=60°. sin[(A+δm)/2]=1.50sin30°=0.75. The angle is 48.59°, so δm≈37.2°.
Small-angle approximation
Thin-prism deviation
For small angles in radians, sinθ≈θ. With air outside, i≈nr₁ and e≈nr₂. Therefore δ=i+e−A≈n(r₁+r₂)−A=(n−1)A.
This approximation requires a small prism angle and small ray angles. Do not use degrees inside the mathematical small-angle approximation without understanding that the ratio is dimensionless; the familiar δ and A can share the same small angular unit for the final proportional form.
Thin prism
n=1.50 and A=6°. δ≈(1.50−1)×6°=3°. A full Snell calculation may differ slightly.
Colour dependence
Why a prism disperses white light
Refractive index varies with wavelength. In ordinary transparent glass, shorter visible wavelengths usually have a larger n and are deviated more than longer wavelengths. A prism therefore spreads white light into a spectrum.
Dispersion is not required to derive monochromatic minimum-deviation geometry, but measuring δm for different colours reveals n(λ). Use a narrow spectral source and safe laboratory procedure; never look into intense beams.
Mixed reasoning
More prism examples
Symmetry check
At minimum deviation with A=50°, r₁=r₂=25°. If i=45°, e must also be 45° and δm=40°.
Base reversal
Turning the prism reverses the direction of deviation relative to the room, but the ray still deviates toward the prism’s new base for the comparable path.
Index comparison
For equal small A, the higher-index prism has larger δ≈(n−1)A.
Wavelength comparison
If nviolet>nred, then thin-prism deviation for violet is greater, producing angular dispersion.
Practical method
Find minimum deviation experimentally
Trace the prism, use a narrow ray or pin alignment and measure deviation for several incidence angles. Plot δ against i; the lowest region estimates δm. At the minimum, check approximate symmetry i≈e.
Keep the prism fixed, mark ray lines widely separated, draw normals accurately and repeat near the minimum with smaller incidence steps. A broad minimum makes one “lowest” reading uncertain, so use the curve and report a range.
Never look into a laser or intense source. Use teacher-approved apparatus and eye-safe alignment. PhET Bending Light can support one-boundary predictions before the two-face experiment.
Exam routine
Seven steps for prism problems
- Draw prism, base and both normals.
- Label i, r₁, r₂, e, A and δ.
- Use r₁+r₂=A.
- Use δ=i+e−A.
- Apply Snell’s law at each face.
- At minimum impose i=e and r₁=r₂.
- Check direction and approximation.
Review plane refraction for Snell fluency and Physical Quantities for angle and unit checks. For online or physical NEB tuition, call 9846662070.
Practice tasks
Closed-book prism checkpoint
- Label all prism angles.
- Derive δ=i+e−A.
- Explain minimum-deviation symmetry.
- Derive the refractive-index relation.
- Solve two δm questions.
- Derive thin-prism deviation.
- Explain dispersion.
- Evaluate a minimum-deviation experiment.
Frequently asked questions
Questions about prism refraction
What is prism angle A?
The angle between the two refracting faces at the apex.
How is total deviation related to the ray angles?
For the usual prism geometry, δ=i+e−A and A=r₁+r₂.
What is special at minimum deviation?
The path is symmetric: i=e and r₁=r₂=A/2.
When can I use δ≈(n−1)A?
For a thin prism and small angles where the small-angle approximation is valid.
Why does a prism disperse white light?
Its refractive index depends on wavelength, so different colours have different deviations.
Where can I get NEB prism help?
For current online or physical tuition options, call 9846662070 and confirm timetable, class mode, teacher availability and fees.
References and next steps
Sources and related study guides
- CDC Nepal: Physics Grade 11
- CDC Nepal: Secondary Curriculum
- OpenStax: Snell Law
- OpenStax Physics: Refraction and Prisms
- OpenStax: Optics Problems
- OpenStax: Concept Questions
- PhET: Bending Light
Continue with the prism study guide for spaced derivation and experiment practice. Curriculum scope and sources were checked on 2 August 2026; follow current CDC, NEB and college instructions if requirements change.
Reversibility and two paths
Why the same deviation can occur twice
For a deviation slightly above the minimum, the δ–i curve has two incidence values. The corresponding paths interchange incidence and emergence when the ray direction is reversed. This is optical reversibility, not two different prism laws.
At the minimum the two paths merge into the symmetric case. Connecting the graph to reversibility explains why i=e is physical evidence rather than an arbitrary shortcut.
Full two-face calculation
Trace a prism when the path is not at minimum deviation
Suppose a prism in air has A=60°, n=1.50 and incidence i=45°. At face 1, sin r₁=sin45°/1.50≈0.4714, so r₁≈28.1°. Geometry gives r₂=A−r₁≈31.9°. At face 2, sin e=1.50sin31.9°≈0.793, so e≈52.5°. Total deviation is δ=i+e−A≈37.5°.
Check that r₁+r₂=60° and that each refraction direction is sensible: air to glass bends toward the first normal; glass to air bends away from the second. Because i and e differ, this is not exactly the minimum-deviation path.
Compare with the minimum
For A=60° and n=1.50, minimum deviation satisfies sin[(60°+δm)/2]=1.50sin30°=0.75. Thus δm≈37.2°, close to but slightly below the calculated 37.5°. The chosen incidence was near the symmetric value.
Thin-prism dispersion
If nviolet=1.54 and nred=1.51 for a small A=5°, deviations are about 2.70° and 2.55°. Angular dispersion is approximately 0.15°. These supplied indices are illustrative; real values depend on material and wavelength.
Deviation curve
Interpret the full incidence range
At very low or very high permitted incidence, the prism path is asymmetric and deviation is larger than its minimum. As i changes, the internal angles and emergence adjust together. The smooth minimum occurs when the path becomes symmetric.
For a deviation above δm, two incidence values may exist. Reversing one ray path interchanges incidence and emergence, showing optical reversibility. At δm the pair merges and i=e.
Applications with boundaries
Prisms can redirect beams, disperse wavelengths and fold optical paths. A right-angle prism can use total internal reflection under suitable index and incidence conditions; a dispersing prism uses wavelength-dependent refraction. Identify which phenomenon is doing the work instead of calling every prism effect “dispersion.”
In measurement, minimum deviation offers a stable symmetry condition for estimating refractive index, but result quality still depends on apex angle, wavelength, alignment and temperature.
Final model check: a complete prism answer includes two normals, medium order at each face, geometry relations, Snell’s law, direction toward the base and a statement of any symmetry or small-angle assumption. Compare the result with the minimum-deviation limit before accepting it. If an inverse-sine argument exceeds one, inspect whether total internal reflection prevents emergence at the second face rather than forcing an angle.
Use a second independently drawn ray diagram to verify the location of the base, both normals and the sign of total deviation before presenting the final complete answer with assumptions stated clearly.
Ask about online or physical tuition
For focused Class 11 and Class 12 subject tuition, lesson clarification, worked-example practice and exam preparation, call 9846662070. Class mode, timetable, teacher availability and fees should be confirmed directly before enrolment.
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