NEB Class 11 • Physics • Heat and Thermodynamics
Ideal Gas: NEB Class 11 Physics Guide
Connect pressure, volume, absolute temperature and amount of gas in one state equation. Use process conditions, kinetic theory and graphs to explain—not merely calculate—gas behaviour.
- Boyle, Charles and pressure laws
- PV=nRT, combined law and kinetic theory
- Processes, graphs, limitations and examples
Curriculum boundary
What Ideal Gas study includes
Use the CDC Physics Grade 11 page and secondary curriculum for current Nepal scope. The institutional OpenStax Ideal Gas Law reference connects experimental gas laws to PV=nRT.
The ideal gas is a model: molecules occupy negligible volume compared with the container and interact negligibly except during collisions. Real gases approach the model best at relatively low density and away from condensation. State variables describe equilibrium states; they do not by themselves explain how fast a state changes.
State description
Pressure, volume, temperature and amount
Pressure is force per unit area created microscopically by molecular momentum changes at walls. Volume is the space available to the gas. Absolute temperature measures thermal state and connects with average translational kinetic energy. Amount can be n moles or N molecules, with N=nNA.
| Variable | SI unit | Common error |
|---|---|---|
| P | Pa | Using gauge instead of absolute pressure |
| V | m³ | Leaving litres unconverted |
| T | K | Using Celsius directly in ratios |
| n | mol | Confusing mass with amount |
Absolute pressure equals gauge pressure plus atmospheric pressure. One litre is 10−3 m³. Kelvin temperature is T/K = t/°C + 273.15 for ordinary conversions.
Controlled-variable laws
Boyle, Charles and pressure laws
For fixed amount at constant temperature, Boyle’s law gives PV=constant, so P∝1/V. For fixed amount at constant pressure, Charles’s law gives V/T=constant. At fixed volume, P/T=constant. Temperature must be absolute in proportional laws.
Boyle example
A gas at 100 kPa occupies 2.0 L and is compressed isothermally to 0.80 L. P₂=P₁V₁/V₂=250 kPa. Pressure rises because molecular collisions with the smaller boundary occur more frequently.
Charles example
At constant pressure, 1.5 L at 300 K warms to 360 K. V₂=1.5×360/300=1.8 L. Using 27 and 87 in a ratio would be physically wrong.
A graph of P against 1/V is straight for an ideal isothermal sample; P against V is a rectangular hyperbola. Extrapolating a real-gas graph to impossible states should not be mistaken for evidence below condensation.
One state equation
PV=nRT and the combined gas law
PV=nRT uses R≈8.31 J mol−1K−1. Equivalently PV=NkBT with kB≈1.38×10−23 J K−1. Since R=NAkB, the two forms describe amount at different scales.
Find number of moles
A gas has P=1.00×105 Pa, V=0.0249 m³ and T=300 K. n=PV/(RT)=1.00×105×0.0249/(8.31×300)≈1.00 mol.
Two-state change
A fixed sample goes from P₁=100 kPa, V₁=2.0 L, T₁=300 K to V₂=1.5 L, T₂=330 K. P₂=P₁V₁T₂/(T₁V₂)=147 kPa approximately.
Cancel fixed n and R to obtain P₁V₁/T₁=P₂V₂/T₂. If gas leaks or is added, n is not fixed; use the full state equation for both states.
Molecular explanation
Kinetic theory behind pressure and temperature
The OpenStax kinetic-theory section derives pressure from molecular momentum transfer and gives PV=(1/3)Nm⟨v²⟩. Combining with PV=NkBT gives average translational kinetic energy per molecule ½m⟨v²⟩=3kBT/2.
At the same temperature, different ideal gases have the same average translational kinetic energy per molecule, not the same root-mean-square speed. Lighter molecules have higher rms speed because vrms=√(3kBT/m).
Thermodynamic paths
Isothermal, isobaric and isochoric changes
Isothermal
T fixed, so PV constant for fixed ideal gas.
Isobaric
P fixed, so V/T constant.
Isochoric
V fixed, so P/T constant.
General change
Use PV=nRT at each equilibrium state and state what changes.
The area under a P–V curve represents work done by the gas in an appropriate thermodynamic treatment. Two paths between the same endpoints can have different work and heat transfers even though state-variable changes match.
Nepal-relevant reasoning
More Ideal Gas examples
Sealed cylinder warming
A fixed rigid cylinder rises from 290 K to 348 K. P₂/P₁=348/290=1.20, so absolute pressure rises 20%. Do not apply this to an open vessel where amount can change.
Flexible balloon at altitude
Lower external pressure tends to allow an approximately flexible balloon to expand, but temperature, elastic tension and leakage also matter. The ideal law supplies a first model, not a complete flight prediction.
Density relation
With molar mass M, n=m/M and ρ=m/V. Substitution gives ρ=PM/(RT). At fixed P, ideal-gas density decreases as absolute temperature increases.
Practical evidence
Test Boyle’s law safely
Trap a fixed amount of air in a sealed syringe connected to an approved pressure sensor. Change volume slowly, record absolute pressure after equilibrium and plot P against 1/V. Keep temperature approximately constant by waiting between compressions and avoiding rapid squeezing.
Uncertainties include syringe dead volume, seal leakage, plunger friction, sensor zero and warming during compression. A non-zero intercept can reveal systematic offset; scatter alone does not prove the model false. Do not use high pressure or unapproved sealed glass apparatus.
Use PhET Gas Properties for prediction–observation–explanation: vary one state variable at a time and explain wall collisions.
Problem routine
Seven steps for an Ideal Gas question
- Define the gas sample and two states.
- Check whether amount is fixed.
- Convert pressure to absolute and temperature to kelvin.
- Convert litres to cubic metres when using R in SI.
- Name constant variables and select the law.
- Calculate symbolically before substitution.
- Check direction, units and model limits.
Review Heat & Temperature for equilibrium and absolute-temperature language and Physical Quantities for conversions. For online or physical NEB tuition, call 9846662070.
Practice tasks
Closed-book Ideal Gas checkpoint
- State ideal-model assumptions.
- Explain pressure microscopically.
- Solve Boyle and Charles examples.
- Convert gauge to absolute pressure.
- Find n using PV=nRT.
- Derive the two-state law.
- Compare molecular speeds at equal temperature.
- Evaluate a syringe experiment.
Frequently asked questions
Questions about the Ideal Gas model
Why must temperature be in kelvins?
Gas-law proportionalities use absolute temperature, whose zero corresponds to the model’s zero-temperature limit.
Should I use gauge or absolute pressure?
Use absolute pressure in gas laws; add local atmospheric pressure to gauge pressure when required.
When can I use the combined gas law?
Use it for two equilibrium states of the same fixed amount of ideal gas.
Do equal-temperature gases have equal molecular speed?
They have equal average translational kinetic energy per molecule; lighter molecules have greater rms speed.
When does a real gas depart from the ideal model?
Departures become important at high density and near condensation, where molecular volume and interactions matter.
Where can I get NEB Ideal Gas help?
For current online or physical tuition options, call 9846662070 and confirm timetable, class mode, teacher availability and fees.
References and next steps
Sources and related study guides
- CDC Nepal: Physics Grade 11
- CDC Nepal: Secondary Curriculum
- OpenStax: Ideal Gas Law
- OpenStax: Kinetic Theory
- OpenStax: Gas Concept Questions
- PhET: Gas Properties
Continue with the Ideal Gas Study Guide for spaced practice and process graphs. Curriculum scope and sources were checked on 2 August 2026; follow current CDC, NEB and college instructions if requirements change.
Model limits
When ideal behaviour becomes unreliable
At high pressure, molecules occupy a non-negligible fraction of the container and their attractions affect pressure. Near condensation, intermolecular forces and phase change dominate. The ideal law can still be a useful approximation, but the question must identify the regime and required precision.
A model is judged by its assumptions and evidence, not by whether it is called “ideal.” Use it to predict trends, compare low-density states and provide a baseline for discussing real-gas departures.
Connections and derivation
Derive useful relations from PV=nRT
For molar mass M, n=m/M. Substitute into PV=(m/M)RT and divide by V to obtain P=ρRT/M, hence ρ=PM/(RT). This predicts lower ideal-gas density at higher absolute temperature when pressure and composition are fixed.
For a fixed amount, compare two equilibrium states: P₁V₁=nRT₁ and P₂V₂=nRT₂. Dividing cancels nR and gives P₁V₁/T₁=P₂V₂/T₂. The cancellation is valid only when the same amount remains inside the boundary.
Dimensional check: Pa·m³=N·m=J, while mol×J mol−1K−1×K also gives J. This confirms dimensional consistency, though not the model assumptions.
Model check: after every result, state what is held fixed, whether the gas amount crosses the boundary, and why the trend agrees with molecular collisions. This verbal line is essential evidence that PV=nRT was selected for the right physical situation. Compare the final state with a limiting case: a smaller volume at fixed temperature should not produce a smaller absolute pressure for the same gas sample.
Always record the chosen equilibrium states clearly.
Ask about online or physical tuition
For focused Class 11 and Class 12 subject tuition, lesson clarification, worked-example practice and exam preparation, call 9846662070. Class mode, timetable, teacher availability and fees should be confirmed directly before enrolment.
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